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7k^2-44k+12=0
a = 7; b = -44; c = +12;
Δ = b2-4ac
Δ = -442-4·7·12
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-40}{2*7}=\frac{4}{14} =2/7 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+40}{2*7}=\frac{84}{14} =6 $
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